http://stackoverflow.com/questions/311165/how-do-you-convert-byte-array-to-hexadecimal-string-and-vice-versa-in-c

Hope it helps!!

The line:
numpad:=substr(result,length(result)-2);

returns the last 2 characters which represent the number of hex characters that have been padded by the .Net padding method (ANSIX923) which is in our example 07.

The .Net padding method (ANSIX923) always pad the string your are encrypting even if the string was of the specified block size. Thus the code always gives you the correct answer.

Thanks,
Suad

We were encrypting data(in the example above) with C# and decrypting it with PL/SQL. Here C# had PaddingMode.ANSIX923 standard followed. If you read how ANSIX923 padding works with encryption you can easily write your decrypter in PL/SQL.

In your case you are encrypting data with PL/SQL. I would suggest that you pad data as per ANSIX923 standard and use C# decryption to decrypt the data. Would work like a charm. Let me know if it works out.

Due to the difference between Oracle and C# I could not decrypt the data on the file, the only possible way is to change the default setting of the Oracle’s built-in dbms_obfuscation_toolkit that generates the file, then we can decrypt data by using C#;

please help me to find solution. oracle pl/sql code is
CREATE OR REPLACE package body sp_crypt as

Function encrypt(unencrypted_string in varchar2)
return varchar2 Is

ls_in_string varchar2(64) := rpad(unencrypted_string,24,’ ‘);
ls_key_string varchar2(64) := ‘b0st0nrs’;
ls_encrypted_string varchar2(256);
lr_in_string raw(2048);
lr_key raw(2048);

Begin

If (ls_in_string is NULL) Then
return(NULL);
Else
lr_in_string := utl_raw.cast_to_raw(ls_in_string);
lr_key := utl_raw.cast_to_raw(ls_key_string);

dbms_obfuscation_toolkit.DESEncrypt(input => lr_in_string,
key => lr_key,
encrypted_data => ls_encrypted_string);

return(ls_encrypted_string);
End If;

End encrypt;

Function decrypt(encrypted_string in varchar2)
return varchar2 Is

ls_key_string varchar2(64) := ‘b0st0nrs’;
lr_key raw(2048) := utl_raw.cast_to_raw(ls_key_string);
ls_unencrypted_string varchar2(64);

Begin

If (encrypted_string is NULL) Then
return(NULL);
Else
dbms_obfuscation_toolkit.DESDecrypt(input => encrypted_string,
key => lr_key,
decrypted_data => ls_unencrypted_string);

return(rtrim(utl_raw.cast_to_varchar2(ls_unencrypted_string)));
End If;

End decrypt;

End sp_crypt;
/

Thanks
Nitin

returns the last three characters, this leed to an error if length of the last block is seven and the last digit of the hex value is != 0.
eg if you encrypt strings like ‘123456#’ or ‘ABCDEFGH123456#’
you can’t decrypt them.
Change line 11 of your listing to:
numpad:=substr(result,length(result)-1);
Then everythink works fine!

Thanks for your excellent example!